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-x^2+0.4x-0.02=0
We add all the numbers together, and all the variables
-1x^2+0.4x-0.02=0
a = -1; b = 0.4; c = -0.02;
Δ = b2-4ac
Δ = 0.42-4·(-1)·(-0.02)
Δ = 0.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.4)-\sqrt{0.08}}{2*-1}=\frac{-0.4-\sqrt{0.08}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.4)+\sqrt{0.08}}{2*-1}=\frac{-0.4+\sqrt{0.08}}{-2} $
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